Williamsburg ranked among safest spring break destinations for 2025

WILLIAMSBURG – Williamsburg is one of the safest places in the nation to travel to for spring break, according to a new study.

Personal injury law firm 844SeeMike conducted an analysis to determine the safest and most dangerous spring break destinations in the United States. The study reviewed a breadth of safety data for 31 popular vacation spots, including DUI incidents, pedestrian safety measures and water activity risks.

Williamsburg ranked #3 on the list of the safest places to visit for spring break 2025 based on the findings, according to a release from the law firm.

The historic city was praised for its “structured and family-friendly atmosphere” as well as its “well-regulated visitor areas” and low crime rates.

Coming in at no. 1 on the list of safest destinations was San Diego, California. Conversely, Daytona Beach, Florida was listed as the most dangerous.

The study’s methodology relied on data from the U.S. Census Bureau, Centers for Disease Control and Prevention and the National Highway Traffic Safety Administration.

Here’s the full list of the safest and most dangerous spring break destinations, according to the firm:

Top 10 safest U.S. spring break destinations for 2025

1. San Diego, California
2. Breckenridge, Colorado
3. Williamsburg, Virginia
4. Cannon Beach, Oregon
5. Austin, Texas
6. Lake Tahoe, California
7. Miami Beach, Florida
8. Tempe, Arizona
9. Los Angeles, California
10. Park City, Utah

Top 10 most dangerous spring break destinations for 2025

1. Daytona Beach, Florida
2. Panama City Beach, Florida
3. Naples, Florida
4. South Padre Island, Texas
5. Myrtle Beach, South Carolina
6. Tucson, Arizona
7. New Orleans, Louisiana
8. Pigeon Forge, Tennessee
9. Charleston, South Carolina
10. Nashville, Tennessee